Resolving Contrasts Error in R Linear Models: 4 Essential Solutions
Based on the provided code, it appears that the main issue is with the lm function in R, which throws an error when trying to fit a linear model due to “contrasts can be applied only to factors with 2 or more levels”.
To resolve this error, several solutions can be explored:
- Drop the offending variable: If there’s no statistical reason to keep the variable with new levels, dropping it from the model is a simple solution.
# Create a sample dataset
set.seed(123)
df <- data.frame(x = rnorm(100), y = rnorm(100))
df$x <- factor(df$x)
# Fit the linear model without the offending variable
model <- lm(y ~ x + other_variable, data = df)
# Print the coefficients
summary(model)
- Replace with a vector of 1: If there’s no need to drop the variable but want to resolve the issue, replace it in the model formula with a vector of 1.
# Create a sample dataset
set.seed(123)
df <- data.frame(x = rnorm(100), y = rnorm(100))
df$x <- factor(df$x)
# Fit the linear model with the offending variable replaced by a vector of 1
model <- lm(y ~ 1 + other_variable, data = df)
# Print the coefficients
summary(model)
- Adjust the model formula per group: If fitting separate models for each category is feasible, this approach allows you to dynamically generate model formulae.
# Create a sample dataset with categorical variables
set.seed(123)
df <- data.frame(x = rnorm(100), y = rnorm(100))
df$group <- factor(rep(c("A", "B"), 50))
# Define the model function for each group
model_group_A <- function() {
lm(y ~ x + other_variable, data = df[df$group == "A", ])
}
model_group_B <- function() {
lm(y ~ x + other_variable, data = df[df$group == "B", ])
}
# Fit the models for each group
model_A <- model_group_A()
model_B <- model_group_B()
# Print the coefficients
summary(model_A)
summary(model_B)
- Use cross-validation: If no statistical solution is possible, using cross-validation can help you estimate the performance of your model on unseen data.
# Create a sample dataset with categorical variables
set.seed(123)
df <- data.frame(x = rnorm(100), y = rnorm(100))
df$group <- factor(rep(c("A", "B"), 50))
# Define the model function for each group
model_group_A <- function() {
lm(y ~ x + other_variable, data = df[df$group == "A", ])
}
model_group_B <- function() {
lm(y ~ x + other_variable, data = df[df$group == "B", ])
}
# Define the cross-validation function
cv_function <- function(model) {
# Split the data into training and testing sets
set.seed(123)
idx_train <- sample(1:nrow(df), nrow(df) * 0.8, replace = TRUE)
df_train <- df[idx_train, ]
df_test <- df[-idx_train, ]
# Fit the model on the training data
model_train <- model()
summary(model_train)
# Predict on the testing data
predictions <- predict(model_train, newdata = df_test)
# Calculate the mean squared error
mse <- mean((df_test$y - predictions)^2)
return(mse)
}
# Define the cross-validation grid
param_grid <- expand.grid(method = c("model_A", "model_B"))
# Perform the cross-validation
results <- lapply(param_grid, function(param) {
model <- ifelse(param$method == "model_A", model_group_A(), model_group_B())
cv_function(model)
})
# Print the results
summary(results)
These solutions can help you resolve the “contrasts error” in R when working with linear models.
Last modified on 2025-05-03